"Von Drives From His Home To His Office In 30 Min. On Number-Coding Days When He Cannot Bring His Car, He Takes The Bus And The Same Trip Takes 51 Min

Von drives from his home to his office in 30 min. On number-coding days when he cannot bring his car, he takes the bus and the same trip takes 51 min. If Vons average driving rate is 35 km/h faster than the average rate of the bus, how far is his office from his home? Pls... answer

 

Answer:

distance = 42.5 km

Step-by-step explanation:

Von drives from his home to his office in 30 min. On number-coding days when he cannot bring his car, he takes the bus and the same trip takes 51 min. If Vons average driving rate is 35 km/h faster than the average rate of the bus, how far is his office from his home?

Given:

time by driving (t1) = 30 min = 30/60 hr

time by taking bus (t2) = 51 min = 51/60 hr

let x = average rate of bus

35 + x = Vons average driving rate

velocity = distance / time

v = d / t

d = vt

distance by driving = distance by taking a bus

(35 + x) × (t1) = (x) × (t2)

(35 + x) × (30/60) = (x) × (51/60)

solve for x

x = 50 km/hr

distance = (51/60 hr)(50 km/hr)

distance = 42.5 km